2x^2+55x-252=0

Solution for 2x^2+55x-252=0 equation:

2x^2+55x-252=0

a = 2; b = 55; c = -252;
Δ = b2-4ac
Δ = 552-4·2·(-252)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-71}{2*2}=\frac{-126}{4}
=-31+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+71}{2*2}=\frac{16}{4}
=4
$